write the zeros of the polynomial (x) = x(x-2) (x-3)
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Answer:
P (x) = x (x 2) (x+3)
To find zeros,
P (x) = 0
.. (x) (x – 2) (x+ 3) = 0
.x = 0 OR x – 2 = 0 OR x 3 = 0
..x = 0 OR x = 2 ORx = -3
.value of x is 0, 2, -3
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