Question

write the zeros of the quadraic polynomial f(x) 6x²-3​

Answer 1

$Given \: Quadratic \: polynomial :$

$p(x) = 6x^{2} - 3$

/* To find zeroes of p(x) , we have take p(x)=0*/

$6x^{2} - 3 = 0$

$\implies 6x^{2} = 3$

$\implies x^{2} = \frac{3}{6}$

$\implies x^{2} = \frac{1}{2}$

$\implies x =\pm \sqrt{ \frac{1}{2}}$

Therefore.,

$\frac{-1}{2} \:and \:\frac{1}{2}\:are \:zeroes$

$of \:6x^{2} - 3$

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