Question

WRITE THREE CONSECUTIVE WHOLE NUMBES OCCURING JUST BEFORE 320001.​

Answer 1

Answer:

$319998, 319999, 320000$

Step-by-step explanation:

Three consecutive whole numbers occurring just before any number $n$ are:

$(n-3),(n-2),(n-1)$

Putting $n=320001$, we get the three numbers as:  $319998, 319999, 320000$ (Ans)