Write three different solutions of 2x + y =0.
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Answered by
1
Step-by-step explanation:
Given equation 2x−y=7
(i)2x−y=7
If x=2 put the equation we get
2×2−y=7
⇒4−y=7
⇒−y=7−4
⇒y=−3
(2,-3)
(ii)2x−y=7
If x=3 put the equation we get
2×6−y=7
⇒6−y=7
⇒−y=7−6
⇒y=−1
(3,-1)
(i)2x−y=7
If x=4 put the equation we get
2×4−y=7
⇒8−y=7
⇒−y=7−8
⇒y=1
(4,1)
Answered by
3
Here is ur answer mate:-
- to find the solution of a equation, means we just have to find the values of x and y.
- Here, as we required 3 different solutions, we have to compute 3 values in the place of either x or y to obtain the solutions of this equation, i.e
→ taking x = 0, we get
2x+y=0
2(0)+y=0
0+y=0
y = 0
So, one solution is (0,0)
→ taking y = 0, we get
2x+y=0
2x+0=0
x = 0/2
So, another solution is (0,0/2)
→ taking x = 1, we get
2x+y=0
2(1)+y=0
2+y=0
y = -2
So, the third solution is (1,-2)
Hence we got all the 3 solution of the equation 2x+y=0. They are -
- 0, 0
- 0, 0/2
- 1/ -2
*u can take any value of either x or y to obtain another's value.
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