Write three different solutions of the equation 2x + 7y = 70 and find the points where it cuts the x-axis and y-axis.
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Answers
Answer:
2x+7y=70
1st solution:
take x=0, 7y=70, y=10
x=0, y=10
2nd solution:
y=0, 2x=70, x=35
x=35, y=0
3rd solution:
take y=2
2x+14=70, 2x=70-14=56, x=28
x=28, y=2
Given : 2x+7y=70
To Find : three different solutions for the equation
the points where it cuts the x axis and y axis.
Solution:
2x+7y=70
x = 0
=> 7y = 70
=> y = 10
Hence cut y axis at ( 0 , 10)
y = 0
=> 2x = 70
=> x = 35
Cut the x axis at ( 35 , 0)
Other three solution
x = 7
=> 14 + 7y = 70
=> 7y = 56
=> y = 8
( 7 , 8 )
x = 14
=> 28 + 7y = 70
=> 7y = 42
=> y = 6
(28 , 6 ) is another solution
x = -7
=> -14 + 7y = 70
=> 7y = 84
=> y = 12
Hence ( -7 , 12) is another solution
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