Math, asked by anmolmandal17, 11 hours ago

Write three different solutions of the equation 2x + 7y = 70 and find the points where it cuts the x-axis and y-axis.

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Answers

Answered by dkchakrabarty01
8

Answer:

2x+7y=70

1st solution:

take x=0, 7y=70, y=10

x=0, y=10

2nd solution:

y=0, 2x=70, x=35

x=35, y=0

3rd solution:

take y=2

2x+14=70, 2x=70-14=56, x=28

x=28, y=2

Answered by amitnrw
1

Given : 2x+7y=70  

To Find :   three different solutions for the equation

the points where it cuts the x axis and y axis.

Solution:

2x+7y=70  

x = 0

=> 7y = 70

=> y = 10

Hence cut y axis at ( 0 , 10)

y = 0

=> 2x = 70

=> x = 35

Cut the x axis at   ( 35 , 0)

Other three solution

x = 7

=> 14 + 7y = 70

=> 7y = 56

=> y = 8

( 7 , 8 )

x =  14

=> 28  + 7y  =  70

=> 7y = 42

=> y = 6

(28 , 6 )  is another solution

x = -7

=> -14 + 7y = 70

=> 7y = 84

=> y = 12

Hence ( -7 , 12)  is another solution

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