Question

Write three different solutions of the equation 2x + 7y = 70 and find the points where it cuts the x-axis and y-axis.
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Answer 1

Answer:

Step-by-step explanation:

2 solutions can be the points where the line cuts x and y axes respectively.

a]For line to cut x axis, y=0

  Putting y=0, 2x+0=70=>x=35

  So one solution can be (35,0)

b]For line to cut y axis, x=0

  Putting x=0, 0+7y=70=>y=10

  So another solution can be (0,10)

c]For third solution, let's divide 70 into two numbers. But 2x is an even number, so 7y also has to be even number (even(2x) + even(7y)=even(70))

Let 70=42+28

2x=42=>x=21

& 7y=28=>y=4, Solution=(21,4)

You can find other such solutions by breaking 70 into two numbers.

The points where line cuts x and y axis are solved in part a and b.

Answer 2

Given : 2x+7y=70  

To Find :   three different solutions for the equation

the points where it cuts the x axis and y axis.

Solution:

2x+7y=70  

x = 0

=> 7y = 70

=> y = 10

Hence cut y axis at ( 0 , 10)

y = 0

=> 2x = 70

=> x = 35

Cut the x axis at   ( 35 , 0)

Other three solution

x = 7

=> 14 + 7y = 70

=> 7y = 56

=> y = 8

( 7 , 8 )

x =  14

=> 28  + 7y  =  70

=> 7y = 42

=> y = 6

(28 , 6 )  is another solution

x = -7

=> -14 + 7y = 70

=> 7y = 84

=> y = 12

Hence ( -7 , 12)  is another solution

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