Math, asked by bablujain182, 7 hours ago

Write three equivalent rational numbers for -5/7, one of which should have denominator (-56).​

Answers

Answered by RvChaudharY50
2

Given :- Write three equivalent rational numbers for -5/7, one of which should have denominator (-56). ?

Solution :-

→ given rational number is = (-5/7)

now, in order to find the equivalent rational numbers for -5/7 we have to multiply both numerator and denominator by same number .

so,

→ Multiply both numerator and denominator by 2 = (-5/7) * (2/2) = (-10/14)

→ Multiply both numerator and denominator by 3 = (-5/7) * (3/3) = (-15/21)

and,

→ for denominator (-56) Multiply both numerator and denominator by 8 = (-5/7) * (8/8) = (-40/56) = 40/(-56)

Learn more :-

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Answered by rohitkumargupta
0

HELLO DEAR,

GIVEN:- Write three equivalent rational numbers for -5/7,

one of which should have denominator (-56).

SOLUTION:-The number \large{\frac{-5}{7}} is rational number.

To obtain number equivalent to \large{\frac{-5}{7}} shout be

Multiple by \large{\frac{2}{2}} , \large{\frac{3}{3}}

and \large{\frac{8}{8}} .

So, the first number equivalent to \large{\frac{-5}{7}} is,

\large{\frac{-5×2}{7×2}} = \large{\frac{-10}{14}}

the second number equivalent to \large{\frac{-5}{7}} is,

\large{\frac{-5×3}{7×3}} = \large{\frac{-15}{21}}

the third number equivalent to \large{\frac{-5}{7}} is,

\large{\frac{-5×8}{7×8}} = \large{\frac{-40}{56}}

The number which is equivalent to \large{\frac{-5}{7}}

and the denominator is (-56) is \large{\frac{-40×-1}{56×-1}}

=> \large{\frac{40}{-56}}

THANKS.

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