write three irrational numbers between 5/7 and 9/11
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Answered by
4
to find irrational numbers firstly we have to divide 5 by 7 & 9 by 11
5÷7= 0.714285....
0.714285 bar upon 714285
9÷11 =0.8181...
0.8181 bar upon 81
the req. irrational no. will lie btwn 0.714285 bar upon 714285 & 0.81 bar upon 81
the req no. are 0.730730073000730000.....
0.7650765007650007650000......
0.80800800080000.....
5÷7= 0.714285....
0.714285 bar upon 714285
9÷11 =0.8181...
0.8181 bar upon 81
the req. irrational no. will lie btwn 0.714285 bar upon 714285 & 0.81 bar upon 81
the req no. are 0.730730073000730000.....
0.7650765007650007650000......
0.80800800080000.....
Answered by
3
just plus the numerators and denominators, cuz the sum of 2 irrational numbers is always irrational - 5/7 and 9/11
= 5+9 and below that write 7+11
=14/18
=(after cutting on 2's table) 7/9
that's the first rational number, u can find the 2nd rational number in the same - just add any 2 of the terms ( u can add 5/7+7/9 or 7/9+9/11 add them in the way i told earlier) :)
= 5+9 and below that write 7+11
=14/18
=(after cutting on 2's table) 7/9
that's the first rational number, u can find the 2nd rational number in the same - just add any 2 of the terms ( u can add 5/7+7/9 or 7/9+9/11 add them in the way i told earlier) :)
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