write three solutions of 3x+y - 8
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JUST SUBSTITUTE VALUES IN X AND Y
FIRST,
3x+y=8
by putting x=0 we get--
3(0) +y=8
y=8 ; x=0 ______1st sol.
by putting x=2
3(2) +y=8
6+y=8
y=2 ; x=2________2nd sol.
by putting y=-1
3(-1) +y=8
-3+y=8
y=11 ; x= -1________3rd sol.
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