write three solutions of te following equation 2x+y=14
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Given: 2x−3y=−14...(1)
3x−2y=−6...(2)
After adding (1) and (2) equations. we get
2x−3y+3x−2y=−14−6
⇒5x−5y=−20⇒x−y=−4...(3)
On subtracting (1) from (2). we get
3x−2y−2x+3y=−6+14
⇒x+y=8...(4)
Now adding (3) and (4). we get
2x=4⇒x=2
By putting x=2 in (3), we get
2−y=−4⇒y=6
∴(2,6) is solution of given equations.
Value of xy=2×6=12.
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2x+y=14. (1)
x-y=1. (2)
2x+y=14
x-y=1
3x=15,x=15/3=5,x=5
5-y=1,y=5-1=4,y=4
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