Write three terms of the GP when the first term ‘a’ and the common ratio ‘r’ are given?
(i) a = 4; r = 3 (ii) a = √5 ; r = 1/5
(iii) a = 81; r = −1/3 (iv) a = 1/64; r = 2
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standard form of a GP is given as..
a , ar , ar² , ar³ , ar⁴ , ........ arⁿ, where a is first term and r is common ratio.
here, ar = 2nd term of the GP
ar² = 3rd term of the GP.
(1) a = 4, r = 3
so, first term = a = 4
2nd term = ar = 4 × 3 = 12
3rd term = ar² = 4 × 3² = 36
(2) a = √5, r = 1/5
first term = a = √5
2nd term = ar = √5 × 1/5 = 1/√5
3rd term = ar² = √5 × 1/5² = 1/5√5
(3) a = 81 , r = -1/3
first term = a = 81
2nd term = ar = 81 × -1/3 = -27
3rd term = ar² = 81 × (-1/3)² = 9
(4) a = 1/64 , r = 2
first term = a = 1/64
2nd term = ar = 1/64 × 2 = 1/32
3rd term = ar² = 1/64 × (2)² = 1/16
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