Question

Write true or false ..The pair of 2x+ y= 5 and x-- y = 1 have a unique solution.​

Answer 1

Answer:

no it's not so unique

u can solve it easily

so, I feel it as false

Step-by-step explanation:

Answer 2

$2x + y = 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ a1x + b1y = c1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ a1 = 2 \: \: \: \: b1 = 1 \: \: \: \: c1 = 5 \\ \\ x - y = 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ a2 + b2 = c2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ a 2 = 1 \: \: \: \: b2 = - 1 \: \: \: \: c2 = 1 \\ \\ \pink{unique \: \: \: solution} \\ \\ \frac{a1}{b1} \blue{not \: \: \: equal \: \: \: to} \frac{b1}{b2} \\ \\ \frac{2}{1} \blue{not \: \: \: equal \: \: \: to} \frac{1}{ - 1}$

TRUE

HOPE IT HELPS TO U