write two arithmetic sequence with 100 as the sum of first four term
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Answered by
1
Step-by-step explanation:
First number be n
Try with different A.P with different difference
1)With difference d=2
n+n+2+n+4+n+6=100
4n+12=100
n=88/4
n=22
Therefore first A.P 22,24,26,28….
2)With difference d=4
n+n+4+n+8+n+12=100
4n=100–24
4n=76
n=19
Second A.P 19,23,27,31…
3)With difference d=6
n+n+6+n+12+n+18=100
4n=100–36
4n=64
n=16
Third A.P 16,22,28,34…
4)With difference d=8
n+n+8+n+16+n+24=100
4n=100–48
4n=52
n=13
Answered by
0
Answer:
1)With difference d=2
n+n+2+n+4+n+6=100
4n+12=100
n=88/4
n=22
Therefore first A.P 22,24,26,28….
2)With difference d=4
n+n+4+n+8+n+12=100
4n=100–24
4n=76
n=19
Second A.P 19,23,27,31…
3)With difference d=6
n+n+6+n+12+n+18=100
4n=100–36
4n=64
n=16
Third A.P 16,22,28,34…
4)With difference d=8
n+n+8+n+16+n+24=100
4n=100–48
4n=52
n=13
Fourth A.P 13,21,29,37
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