Question

write two numbers whose sum is -5 and product is +6
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Answer 1

Step-by-step explanation:

Let the two numbers be'a'and'b'

a+b=(-5)-----(equation 1)

ab=6---------(equation 2)

b=(6/a)------(equation 3)

putting value of equation 3 in equation 1

a+(6/a)=(-5)

(a^2+6)/a=(-5)

(a^2+6)=(-5a)

a^2+5a+6=0

a^2+3a+2a+6=0

a(a+3)+2(a+3)=0

(a+2)(a+3)=0

a+2=0 or a+3=0

a=(-2) or a=(-3)

b=(-3) or b=(-2)

Answer 2

xy = -5

x + y = 6

p^2 - (x+y)p + (xy) = 0

p^2 -(-5)p + 6 = 0

p^2 + 5p + 6 = 0

p^2 + 2p + 3p + 6 = 0

p(p + 2) + 3(p + 2) = 0

p + 2 = 0 and p + 3 = 0

p = -2, -3

now,

two numbers are x, y are -2, -3

sum of the two numbers

x + y = -2 + (-3)

x + y = -2 -3

x + y = -5

product of two numbers

xy = -2(-3)

xy = 6

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