write two polynomial 2 zeros each
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solution :-
assuming one expression,
P(x) = x² + 2x - 15
by , solving the above equation we get,
x² + 2x- 15= ( x +5) ( x -3) = 0
= > x = -5, x= 3.
So, this second degree polynomial has two zeroes or roots.
similarly, second expression,
P(x) = x² - 14x + 49
by, solving the abvove equation we get,
x² - 14x + 49= ( x - 7 )² = 0
=> x= 7.
so. this is also a second degree polynomial having two zeros or roots...
assuming one expression,
P(x) = x² + 2x - 15
by , solving the above equation we get,
x² + 2x- 15= ( x +5) ( x -3) = 0
= > x = -5, x= 3.
So, this second degree polynomial has two zeroes or roots.
similarly, second expression,
P(x) = x² - 14x + 49
by, solving the abvove equation we get,
x² - 14x + 49= ( x - 7 )² = 0
=> x= 7.
so. this is also a second degree polynomial having two zeros or roots...
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