Question

write vertices of rectangle bounded between the lines x=-5,x=3,y=-2 and y=7​

Answer 1

The vertices of the rectangle ABCD are

A(-5,7), B (-5,-2) , C(3,-2) and D (3,7)

Step-by-step explanation:

Given lines are

x=-5.(1)

x=3..(2)

y= -2..(3)

y=7​..(4)

placing these lines on the graph we get to know that the intersection of these lines form a rectangle

therefore , The vertices of the rectangle ABCD are

A(-5,7), B (-5,-2) , C(3,-2) and D (3,7)

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Write the equation of a hyperbola with vertices and co-vertices

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Answer 2

Given:

x=-5

x=3

y=-2

y=7

To find:

vertices of rectangle=?

Solution:

Four lines x = -5, x = 3, y = -2 and y = 7 are visible.  

Therefore there is a P(-5,-2) with the points x =-5 and y =-2.  

The codes where x = 3 and y =-2 meets are Q(3,-2).  

The points where R(3,7) crosses x = 3 and y = 7. R(3, 7).  

The point where x = -5 and y = 7 meets S(-5,7) are given to coordinates.  

There are therefore four vertices (-5,-2), (3,-2), (3,7), and (-5,7) of the rectangle.

The final points are: "(-5,-2), (3,-2), (3,7), and (-5,7) ".