Write whether the following pair of Linear equation is consistent or not x+t=14;x-y=4
Answers
Answered by
12
x+y-14=0
x-y-4=0
They are inconsistent
a1=1,a2=1
b1=1,b2=-1
c1=-14
c2=-4
So
a1/a2 is not equal to b1/b2 not equal to c1/c2.
So they are not consistent.
Answered by
7
x+y-14=0
x-y-4=0
They are inconsistent
a1=1,a2=1
b1=1,b2=-1
c1=-14
c2=-4
So
a1/a2 is not equal to b1/b2 not equal to c1/c2.
So they are not consistent.
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