Question

Write whether the pair of linear equation x+y=14 and x-y=4 is consistent or not if consistent then what are the solutions

Answer 1

Answer:

{$x,y$} = {9,5}

Step-by-step explanation:

The two linear equations are not consistent as $\frac{a1}{a2}$≠$\frac{b1}{b2}$.

Let us compare the two equations,

Subtracting x-y=4 from x+y = 14,

$x+y=14$

$x-y=4$

∴$2x = 18$

∴$x=[tex]\frac{18}{2}$

∴$x=9$

Substituting the value of $x$ in $x+y=14$

∴$9+y =14$

∴$y = 14 -9$

∴$y=5$

∴The solution for the pair of linear equations is {9,5}.

Thank you :) <3

Answer 2

x+y=14
x-y=4
_____
2x-2y =18
divide by 2,we get
x-y=9::::::::::::::::1
___________________
x+y=14
x-y=4
______
x+y=10. :::::::::::::::::::2
adding 1 and 2
we get x