Math, asked by rageon448, 1 day ago

Write x²+ 2x - 8 in the form (x + m )²+n
where m and are integers​

Answers

Answered by nsree0482
0

Answer:

(x+1)²-9 m = 1 n = 9

Explanation

Convert to required form: (x+1)²-9 m 1 n = -9 1 m = n = 9

Answer: (x+1)²-9

m=1

n=-9

Answered by pulakmath007
2

+ 2x - 8 = (x + 1)² - 9 which is of the form (x + m)² + n where m = 1 , n = - 9

Given :

The expression x² + 2x - 8

To find :

Write x² + 2x - 8 in the form (x + m)² + n where m and are integers

Solution :

Step 1 of 2 :

Write down the given expression

Here the given expression is x² + 2x - 8

Step 2 of 2 :

Express in the form (x + m)² + n

\displaystyle \sf   {x}^{2}  + 2x - 8

\displaystyle \sf   =  {x}^{2}  + 2.x.1 +  {1}^{2} -  {1}^{2}   - 8

\displaystyle \sf   =  {(x + 1)}^{2}   -1 -  8

\displaystyle \sf   =  {(x + 1)}^{2}   -9

which is of the form (x + m)² + n where m = 1 , n = - 9

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