Question

write x2 -4=0 in the form of ax2 +bx+c =0​

Answer 1

x² - 4x + 4 = 0

so, we have to find nature of roots

we know if the value if discriminant (D) = 0 (so , roots are real and equal)

if (D) <0(so, roots are imaginary & not equal)

if ( D ) > 0 (so, roots are real but not equal)

so, here in the equation,

x² - 4x + 4 = 0

where, a = 1 , b = -4 , c = 4

D = b² - 4ac

D = (-4)² - 4(1)(4)

D = 16 - 16

D = 0

here, D = 0 so, following the condition roots are real and equal.

Answer 2

Answer:

x2-4 =0

(x^2-2^2)=0

(x-2)(x+2)=0

=x^2-0x-4=0