Question

Write y as a function of x:
x = 8y^3+12y^2+6y-5

Answer 1

Answer:

Sum of 5/8 and -11/12 = 5/8 + (-11/12)

= 5/8 – 11/12

= (5 × 3) – (11 × 2)

= 5/8 – 11/12

= [(5 × 3) – (11 × 2)]/24

(∵ LCM of 8 and 12 = 24)

= (15 – 22)/24 = -7/24

Now, difference of 3/7 and 5/14

= 3/7 – 5/14 or 5/14 – 3/7

= [(3 × 2) – (5 × 1)]/14 or [5 – (3 × 2)]/14

(∵ LCM of 7 and 13 = 14)

= (6 – 5)/14 or (5 -6)/14 = 1/14 or -1/14

Now divide -7/24 by 1/14 or -1/14

= (-7/24/1/14) or (-7/24 × (-14/1)

= (-7/24) × 14/1 or -7/24 × -14/1

= -49/12 or 49/12 = -4. 1/12 or 4. 1/12