Question

Write 'y' in terms of x' for equation 3x-y=2 check whether (-1.3)
is a point on the line.​

Answer 1

Answer:

we have ,3x-y=2

3x-2=y

given point (-1,3)

put x=-1and y=3 in above equation

3(-1)-2=3

-3-2=3

-5=3

which is no true ,so given point is not a solution of equation

Answer 2

Answer:

Required equation is y = 3x - 2,

(-1, 3) does not lie in the line.

Step-by-step explanation:

Here, the given equation,

3x - y = 2,

3x = 2 + y

3x - 2 = y

So, the required equation in the term of y,

$y = 3x - 2$

Now, a point lies in a line if the point satisfies the equation of the line.

Given point is (-1, 3),

$3=3(-1)-2$ ( False )

Hence, (-1, 3) does not lie in the line.

#Learn more :

Check whether the point lies on the line :

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