Question

Write your question here (Keep it simple and clear to get the best answer) 2log8+log25-log16

Answer 1

Answer:

2log8+log25-log16 = 2

Step-by-step explanation:

$2 log(8) + log(25) - log(16)$

$= 2 log( {2}^{3} ) + log( {5}^{2} ) - log( {2}^{4} )$

$= (2 \times 3) log(2) + 2 log(5) - 4 log(2)$

$= 2 log(2) + 2 log(5)$

$= 2( log(2) + log(5) )$

$= 2 log(5 \times 2) = 2 log(10)$

$= 2(1) = 2$

Note:

$log(10) = log_{10}(10) = 1$