Write your question here (Keep it simple and clear to get the best answer)if the diagonal of a square is 8cm.what is the area of a square ?
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Here, ABCD is a square.
Let AB=BC=CD=AD=a [ All sides of square are equal ]
⇒ AC=8cm [ Given ]
In right angled △ABC,
⇒ (AC)2=(AB)2+(BC)2 [ By Pythagoras theorem ]
⇒ (8)2=a2+a2
⇒ 64=2a2
⇒ a2=32
⇒ Area of a square =a2=32cm2
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