Write your question here (Keep it simple and clear to get the best answer)calculate the maximum pressure a glass block of density 2.5gcm would exert on a horizontal surface, if the block measures 20cm ×10cm ×5cm
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Dimensions of block = 20cm × 10cm × 5cm
Density of glass block = 2.5g/cm³
Therefore, volume of the block
= 20 × 10 × 5
= 1000cm³
Mass = Density × volume
= 2500g
= 2.5kg
Force = 2.5kgf
= (2.5 × 10)N
= 25N
Area of cross-section = 200cm² (20×10)
Now, according to Blaise Pascal
Pressure = Force / Area of cross-section
= 25 / 200
= 1/8
= 0.125Pa
Hope you understood, cheers :)
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