Question

writewrite a program to input 10 numbers into an integer array and check whether all the numbers are three digit numbers or not also do the Java program by using scanner class​

Answer 1

Answer:

Program:-

//Program using Scanner class

import java.util.*;

public class Brainly_Answer

{

public static void main(String args[ ])

{

Scanner in=new Scanner(System.in);

int c=0;

System.out.println("Enter the elements");

int a[ ]=new int[10];

for(int i=0;i<a.length;i++)

{

a[i]=in.nextInt();

}

for(int i=0;i<a.length;i++)

{

if(a[i]>=100&&a[i]<1000)

c++;

}

if(c==10)

System.out.println("All the numbers are three digit numbers");

else

System.out.println("All the numbers are not three digit numbers");

}

}

• The first photo is the program
• The second photo is the input I entered all three digit numbers
• The third photo is the output for the input of all three digit numbers
• The fourth photo I entered all randomly added numbers input
• The fifth photo is the output for all random input numbers

Logic:-

• Logic is simple first we create an array of size 10
• We now enter the elements using a for loop
• We now run the same for loop and check the condition
• If it is true it iterates c
• If c==10 I.e the length you may also write if c==a.length it prints all numbers as three digit numbers else prints all numbers are not three digit numbers.

Answer 2

Answer:

Explanation:

import java.util.*;

class threeDigit

{

static void main()

{

Scanner sc=new Scanner(System.in);

int a[]=new int[10],i;

boolean f=true;

System.out.println(“Enter 10 numbers:”);

for(i=0;i<10;i++)

a[i]=sc.nextInt();

for(i=0;i<10;i++)

{

if(!(a[i]>=100 && a[i]<=999))

f=false;

}

if(f)

System.out.println(“All are 3 digit numbers”);

else

System.out.println(“All are not 3 digit numbers”);

}

}