Question

wrong ans will be reported​

Answer 1

Answer:-

• 60% less.

According to the question:-

Estimated average number of shoppers in the original store at any time (N) is 45. In the question, it states that, in the new store, the manager estimates that an average of 90 shoppers per hour (60 minutes) enter the store, which is equivalent to 1.5 shoppers per minute (r).

Solution:-

➡The manager also estimates that each shopper stays in the store for an average of 12 minutes (T).

➡Thus, by Little's law, there are, on average, N=rT=(1.5)(12)=18 shoppers in the new store at any time. This is

➡45−18/45*100=60percent less than the average number of shoppers in the original store at any time.

• The final answer is 60.

Answer 2

Answer:$\mathscr{\huge{\red{HELLO}}}$

➡According to the original information given, the estimated average number of shoppers in the original store at any time (N) is 45. In the question, it states that, in the new store, the manager estimates that an average of 90 shoppers per hour (60 minutes) enter the store, which is equivalent to 1.5 shoppers per minute (r). ➡The manager also estimates that each shopper stays in the store for an average of 12 minutes (T). Thus, by Little's law, there are, on average, N=rT=(1.5)(12)=18 shoppers in the new store at any time. This is

➡45−18/45*100=60percent less than the average number of shoppers in the original store at any time.

➡The final answer is 60.