Question

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Answer 1

Correct Question:

Find value of x, if

$\tt \dfrac{9x+0.5}{5} - \dfrac{2x+3}{4} = 0$

Your Answer:

Taking LCM in the first Step.

So, LCM of 5 and 4 is 20

$\tt \Rightarrow \dfrac{4(9x+0.5)-5(2x+3)}{20} = 0 \\\\ Now \ \ its \ \ turn \ \ to \ \ solve \ \ the \ \ brackets \\\\ \tt \Rightarrow \dfrac{36x + 2 - 10x -15}{20} = 0 \\\\ \tt \Rightarrow \dfrac{26x-13}{20} = 0 \\\\ Taking \ \ 0 \ \ to \ \ Right \ \ side \\\\ \tt \Rightarrow 26x-13 = 0\times 20\\\\ \tt \Rightarrow 26x-13 = 0 \\\\ \tt \Rightarrow 26x = 13 \\\\ \tt \Rightarrow x =\dfrac{13}{26} \\\\ \tt \Rightarrow x = \dfrac{1}{2} \ or \ x = 0.5$

Concepts Used:

• Solving for a variable
• LCM of Numbers
• Cross Multiplication
• Mathematical Solvings.