Question

wrong answers will be reported!!!!!​

Answer 1

$\huge\mathfrak\red {Answer:}$

(i) <CAB = 180° - 120° (as <MAC + <CAB form a linear pair)

→ <CAB = 60°

(ii) <ABC = 180° - 130° (as <MBN + <ABC form a linear pair)

→ <ABC = 50°

(iii) <ACB = 180° - (60 + 50)° (as <CAB + <ABC + <ACB = 180° according to Angle sum property of triangles)

→ <ABC = 180° - 110°

→ <ACB = 70°

(iv) <BCD = 180° - 70° (as <ACB + <BCD form a linear pair)

→ <BCD = 110°

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Answer 2

Step-by-step explanation:

(i) <CAB = 180° - 120° (as <MAC + <CAB form a linear pair)

→<CAB = 60°

(ii) <ABC = 180° - 130° (as <MBN + <ABC form a linear pair)

→ <ABC = 50°

(iii) <ACB = 180° - (60 + 50)° (as <CAB + <ABC + <ACB = 180° according to Angle sum property of triangles)

ANSWER

→ <ABC = 180° - 110°