Question

wrong answers will be reported!​

Answer 1

Given :-

• y = 3x²

To Prove :-

• log₃ y = 1 + 2log₃ x

Solution :-

Given that,

⇒ y = 3x²

Taking log with the base 3 both sides. As the base of the log in the question is 3, So

⇒ log₃ y = log₃ (3x²)

⇒ log₃ y = log₃ ( 3 • x² )

⇒ log₃ y = log₃ 3 + log₃ x²

[ As, logₙ (a • b) = logₙ a + logₙ b ]

⇒ log₃ y = 1 + log₃ x²

[ As, logₙ n = 1 ]

⇒ log₃ y = 1 + 2log₃ x

[As, logₘ aⁿ = n logₘa ]

Hence, Proved!

Some Information :-

• Base of log of any number should always be greater than 0 and also not equal to 1.

Below are some useful formulas:

• logₘ 1 = 0
• logₘn = 1 / logₙm
• logₘ x/y = logₘ x - logₘ y
• logₑ x = ln x

Answer 2

Answer:

hopefully it will work ☺️☺️