wS. In the adjoining figure, POR is a straight line and OS is common ray to both angles ZPOS and ZROS. Find the value of x, if ZPOS = (5x + 28) and ZROS = (4x - 10). Also find ZPOS and ZROS. = (5x + 28) (4x - 10° - Р O R
Answers
Answer:
It is given that OR is perpendicular to PQ
So that POR = 90°
sum of angle in linear pair always equal to 180°
ZPOS + ZSOR + <POR = 180°
Plug POR = 90°
90°+2SOR + <POR = 180°
ZSOR + <POR = 90°
ZROS = 90° ZPOS
- (1)
ZQOR = 90°
Given that OS is another ray lying between rays
OP and OR so that
ZQOS - ROS = 90°
ZROS=ZQOS - 90°
(2)
On adding equations (1) and (2), we obtain
2 ZROS = <QOS - ZPOS
ZROS = 1/2(2QOS-ZPOS)
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Step-by-step explanation:
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Answer:
It is given that OR is perpendicular to PQ
So that POR = 90°
sum of angle in linear pair always equal to 180°
ZPOS + ZSOR + <POR = 180°
Plug POR = 90°
90°+2SOR + <POR = 180°
ZSOR + <POR = 90°
ZROS = 90° ZPOS
- (1)
ZQOR = 90°
Given that OS is another ray lying between rays
OP and OR so that
ZQOS - ROS = 90°
ZROS=ZQOS - 90°
(2)
On adding equations (1) and (2), we obtain
2 ZROS = <QOS - ZPOS
ZROS = 1/2(2QOS-ZPOS)