Question

wt is value of of x in log ( x+ 2 ) - log (x-1)= log 2​

Answer 1

Answer:-

$\sf \log(x + 2) - \log(x - 1) = \log2$

$\sf \implies \log( \frac{x + 2}{x - 1} ) = \log2$

$\sf \implies \frac{x + 2}{x - 1} = 2$

Taking out log from both the side, we get,

$\sf \implies x + 2 = 2x - 2$

$\sf \implies 2x - x = 2 + 2$

$\sf \implies x =4$

Hence, the value of x is 4.

Answer 2

Answer:

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