Wthout calculating find the value of (2-a)^3 +(2-c)^3 -3(2-a)(2-b)(2-c), if a+b+c =6
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Step-by-step explanation:
By using the identity - a*3 + b*3 + c*3- 3abc = (a+b+c)(a*3+ b*3 +c*3-ab-bc-ac)
here a= (2-a)
b=(2-b)
c=(2-c)
by putting in values we get
(2-a)*3 + (2-b)*3 + (2-c)*3-3(2-a)(2-b)(2-c)=
Now you can calculate the value easily
But,by the way your question is not complete.
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