Wtite the condituins to be satisfied by q so that a rational number p/q had non terminating expansion
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let x/q be the given rational number.
If the prime factorization of q is of the form 2n×5m where n, m are non-negative integers. Then q has a decimal expansion which terminates.
MARK BRAINLIEST
If the prime factorization of q is of the form 2n×5m where n, m are non-negative integers. Then q has a decimal expansion which terminates.
MARK BRAINLIEST
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Hey Dude here u go...
Let x be a rational number which is in the form p/q, where p/q are integer and q is not equal to zero then
◆ x is a terminating decimal only when q is the form (2^m × 5^n) for some non negative integer (0,1,2...) m and n.
◆ x is a non terminating repeating decimal, if q is not equal to (2^m × 5^n) .
So clearly
◆q = (2^m × 5^n) for some non negative integersm and n then p/q is a terminating decimal.
e.g. 7/10
◆ If q is not equal to (2^m × 5^n) then p/q is a non terminating repating decimal.
e.g. 7/15
Let x be a rational number which is in the form p/q, where p/q are integer and q is not equal to zero then
◆ x is a terminating decimal only when q is the form (2^m × 5^n) for some non negative integer (0,1,2...) m and n.
◆ x is a non terminating repeating decimal, if q is not equal to (2^m × 5^n) .
So clearly
◆q = (2^m × 5^n) for some non negative integersm and n then p/q is a terminating decimal.
e.g. 7/10
◆ If q is not equal to (2^m × 5^n) then p/q is a non terminating repating decimal.
e.g. 7/15
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