Question

wuct.
Find the product.
0 (a) x (2a22) * (4a26)​

Answer 1

The value of $a^{2}$ × 2 $a^{22}$ × 4 $a^{26}$ is

"8·$a^{48}$".

Step-by-step explanation:

We have,

$a^{2}$ × 2 $a^{22}$ × 4 $a^{26}$

= (2 × 4)·$a^{2}$ ·$a^{22}$ ·$a^{26}$

= 8·$a^{2 + 22 + 26}$

[ ∵$a^{m}$·$a^{n}$ = $a^{m + n}$ ]

= 8·$a^{48}$

Hence, $a^{2}$ × 2 $a^{22}$ × 4 $a^{26}$ =

"8·$a^{48}$".