Question

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4) Find the sumof squares of natural numbers
from 101 25.​

Answer 1

Answer:

According to the question let the two natural numbers be x and y with the assumption that x>y.

As per the question the given equation is like this:

x^2-y^2=101, which can be written as:-

(x+y)*(x-y)=101…..(a)

Now as we have one equation, we can assume that x-y=1, ie x and y are two consecutive natural numbers. Hence x+y=101 as per equation (a).

x-y=1……..(1)

x+y=101…(2)

Solving the two simultaneous equation, we get;

x=51 and y=50.

So we got two numbers as 51 and 50.

So,

Sum of the squares of the two numbers=51^2+50^2=5101.

HOPE IT HELPS. Happy Reading!.