Question

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If the HCF of 180 and 432 is expressed as (180m432m), where m and n are integers, then what is the difference between m and n ​

Answer 1

Answer:

Find the prime factorization of 180

180 = 2 × 2 × 3 × 3 × 5

Find the prime factorization of 432

432 = 2 × 2 × 2 × 2 × 3 × 3 × 3

To find the HCF, multiply all the prime factors common to both numbers:

Therefore, HCF = 2 × 2 × 3 × 3

HCF = 36