Question

x/0.01+(y+0.03/0.05)=y/0.02+(x+0.03/0.04)=2 than values of x and y

Answer 1

x/0.01 + ( y + 0.03/0.05) = 2
⇒100x + (y + 3/5) = 2
⇒ 500x + 5y + 3 = 10
⇒ 500x + 5y = 7 ------(1)

Again, y/0.02 + (x + 0.03/0.04) = 2
⇒50y + x + 3/4= 2
⇒ 200y + 4x + 3 = 8
⇒4x + 200y = 5 --------(2)

equation (2) × 125 - equation (1),
125(4x + 200y ) - 500x + 5y = 125 × 5 - 7
⇒500x + 25000y - 500x + 5y = 625 - 7
⇒ 25005y = 618
⇒ y = 618/25005 = 0.02471 , put it in equation (1)

500x = 7 - 5y = 7 - 5 × 0.2471
⇒ x = 0.01375

Answer 2

Thanks for the question!

It is definitely a very interesting question to solve and do some brainstorming.

**************************************************


x/0.01 + ( y + 0.03/0.05) = 2
100x + (y + 3/5) = 2
500x + 5y + 3 = 10
500x + 5y = 7 ------(A)

y/0.02 + (x + 0.03/0.04) = 2
50y + x + 3/4= 2
200y + 4x + 3 = 8
4x + 200y = 5 --------(B)

equation (B) × 125 - equation (A),
125(4x + 200y ) - 500x + 5y = 125 × 5 - 7
500x + 25000y - 500x + 5y = 625 - 7
 25005y = 618
y = 618/25005 = 0.02471

We have, 500x = 7 - 5y = 7 - 5 × 0.2471
x = 0.01375

**************************************************
Hope it helps and solves your query!!