Question

X 0.39. Ram and shyam start simultaneously from point A towards B, 60 km 0/4
apart. Ram's speed is 4km/hr. less than shyam's speed. Shyam after
reaching B turns back and meets Ram at a distance 12km from B. Find
Ram's speed.
A
O 8 km/hr
O 7 km/hr
X
O 9 km/hr
0 10 km/hr​

Answer 1

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$\huge\underline{\underline{\red{\mathfrak{solution:}}}}$

$\bigstar$ 20 kmph

Explanation:

AB = 60 km

Ram's speed = x kmph

Shyam's speed = y kmph

Case I,

$\tt{ \frac{60}{x}− \frac{60}{y} = 1 ––––– (i)}$

Case II,

$\tt{ \frac{60}{y}− \frac{60}{2x} = 3060 = 12 ––––– (ii)}$

On adding equations (i) and (ii).

$: \implies \tt{ \frac{60}{x}− \frac{60}{2x} = 1+12}$

$: \implies \tt{ \frac{60}{x}− \frac{30}{x }= 32}$

$: \implies \tt {\frac{ 60−30}{x }= 32}$

$: \implies \tt { 3x = 30 × 2 }$

$: \implies \tt x = 30×23 = 20 kmph$

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