Question

(X+0.5)+1/2(3x-1/3)=1/3(X+1)​

Answer 1

follow this process...

Step-by-step explanation:

if any doubt..msg me...I'll explain

Answer 2

Question:

$</u><u>\</u><u>b</u><u>f</u><u>\</u><u>g</u><u>r</u><u>e</u><u>e</u><u>n</u><u> </u><u>{</u><u>(x + 0.5) + \frac{1}{2} (3x - \frac{1}{3} ) = \frac{1}{3} (x + 1)</u><u>}</u><u>$

Solution-

$</u><u>\</u><u>s</u><u>f</u><u> </u><u>{</u><u>⟶(x + \frac{1}{2} ) + \frac{3x}{2} - \frac{1}{6} = \frac{1}{3} x + \frac{1}{3} </u><u>}</u><u>$

$</u><u>\</u><u>s</u><u>f</u><u> </u><u>{</u><u>⟶x + \frac{3x}{2} - \frac{x}{3} = \frac{1}{3} - \frac{1}{2} + \frac{1}{6} </u><u>}</u><u>$

(collecting all the like terms)

$\sf {⟶ \frac{6x + 9x - 2x}{6} = \frac{2 - 3 + 1}{6}}$

$\sf {⟶ \frac{15x - 2x}{6} = \frac{ - 1 + 1}{6}}$

$\sf {⟶ \frac{13x}{6} = \frac{0}{6}}$

$\sf {⟶ \frac{13x}{6} = 0}$

$\sf {⟶13x = 6 \times 0}$

$\sf {⟶13x = 0}$

$\sf {⟶x = \frac{0}{13}}$

$\sf\blue {⟶x = 0 \: ans..}$

So, the value of x is 0.