Question

{[(x-0)(x-1)(x-4)] ÷-6}×6​

Answer 1

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Answer 2

Answer:

Check my solution ;)

Step-by-step explanation:

{[(x)(x² - 5x + 4)] ÷ -6}x6

(x³ - 5x² + 4x) ÷ -6 × 6

Cancel out the -6 and 6 it will be negative 1

-6/6 = -1

and it will be like this

(x³ - 5x² + 4x ) ● -1

Then multiply x³ - 5x² + 4x to -1

-x³ + 5x² - 4x

If they want it to be in standard form the leading term should not be negative, hence it will be

x³ - 5x² + 4x = 0