X^+1=0 has no real zeros why
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x² + 0+ 1 has no real roots becoz
when discriminant Is negative then roots are imaginary
so here d = 0-4X1X1
= -4
SINCE D NEGATIVE THE ROOTS ARE NOT REAL
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Answer:
+1, has discriminan =b2−4ac=02−4(1)(1)=−4<0
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