Question

x + 1 = 0, x being a positive integer .

Answer 1

here's your answer

Simplify the equation by taking lcm of x and 1/x and u obtain the following equation

x^2 + 1/x >2 then take x on other side

x^2 + 1 >2x and then take 2x to left side

x^2 - 2x + 1> 0 and hence can be written as

( x-1)^2 > 0

As u can find the values of x for above inequation which is real number iex€R

But above we mentioned x cannot be negative real numbers so x can only belong to positive real numbers

So this inequation is not only valid for positive integers but for all positive real numbers(which includes even positive real number)

I hope it helps mark me in brainlist