Question

(x-1)¹⁰⁰¹(2x+1)²⁰⁰¹(3x-2)²⁰²⁰(x-2)¹⁰⁰⁰ greater than equal to 0​

Answer 1

Step-by-step explanation:

(i)

7

1

(3x−5)

2

=28

Simplifying the equation,

⇒(3x−5)

2

=28×7

⇒(3x−5)

2

=196

⇒9x

2

−30x+25=196

⇒9x

2

−30x+25−196=0

⇒9x

2

−30x−171=0

Dividing the whole equation by 3, we get

⇒3x

2

−10x−57=0

⇒3x

2

−19x+9x−57=0

⇒x(3x−19)+3(3x−19)=0

⇒(x+3)(3x−19)=0

⇒(x+3)=0 or (3x−19)=0

⇒x=−3 or 3x=19

⇒x=−3 or x=

3

19

∴ Value of x=−3,

3

19

(ii) 3(y

2

−6)=y(y+7)−3

Simplifying the equation,

⇒3y

2

−18=y

2

+7y−3

⇒3y

2

−18−y

2

−7y+3=0

⇒2y

2

−7y−15=0

⇒2y

2

−10y+3y−15=0

⇒2y(y−5)+3(y−5)=0

⇒(2y+3)(y−5)=0

⇒(2y+3)=0 or (y−5)=0

⇒2y=−3 or y=5

⇒y=−

2

3

or y=5

∴ Value of y=−

2

3

,5

Answer 2

Answer:

correct answer is 0

Step-by-step explanation:

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