Math, asked by navmander01, 10 months ago

(x+1)²=0 has how many real roots

Answers

Answered by nehap0327
0

Answer:

2 real roots

Step-by-step explanation:

Answered by bl200320
0

Answer:

(x+1)²=0 has one real root

(x+1)²=0

x+1=√0= 0

By transposing 1 to other side, we get

x=0-1

Therefore, x= -1

-1 is the only real root of (x+1)²= 0

Hope this helps you.

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