Question

x - 1 + 2(1 - x)^2 - 3x + 3 plss factorise

Answer 1

x-1+2(1 - x)²-3x+3

= x-1-2(x-1)²-3(x-1)

=(x-1){-2(x-1)²-3}

= (x-1){-2(x²-2x+1)-3}

= (x-1)(-2x²+4x³-2-3)

= (x-1)(-2x²+4x³-5)

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Answer 2

solution:-

=> x - 1 + 2(1 - x)^2 - 3x + 3

=> x - 1 + 2 ( 1 - 2x - x² ) - 3x + 3

=> x - 1 + 2 - 4x - 2x² - 3x + 3

=> - 2x² + x - 4x - 3x- 1 + 2 + 3

=> 2x² - x + 4x + 3x + 1 - 2 - 3

=> 2x² + 6x - 4

=> 2x² + 4x + 2x - 4

=> 2x( x + 2 ) - 2 ( x + 2 )

=> ( 2x - 2 ) ( x + 2 )

also we can solve it... after factorise.

let,....

=> 2x - 2 = 0 or x + 2 = 0

=> 2x = 2 or x = - 2

=> x = 2/2 or x = - 2

=> x = 1 or x = - 2

i hope it helps you.