Question

(x+1)/2+2/(x+1)=(x+1)/3+3/(x+1)-5/6
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Answer 1

Answer:

Let us Take is

(x+1)/2+2/(x+1)=(x+1)/3+3/(x+1)-5/6

I hope ur real number are one site and other site is x by numerical

(X+1)/2-(x+1)/3+5/6=3/(x+1)-2/(x+1)

Take both site LCM

[(X+1)*3-(x+1)*2+5)]/6=3-2/(x+1)

(3x+3–2x-2+5)(x+1)=1*6

(X+6)(x+1)=6

X^2+x+6x+6=6

X^2+7x+6–6=0

X^2+7x=0,. x(x+7)=0

Consider that x=0 ,x+7=0

So that answer is x=0,-7