Math, asked by avik3, 1 year ago

x+1/2+2/x+1=x+1/3/+3/x+1-5/6 solve the equation

Answers

Answered by NIMISHGUPTA
16
x+1/2+2/x+1=x+1/3+3/x+1-56
taking L.C.M
(2x^2+3x+4)/4=(6x^2+3x+18)/3
2x^2+3x+4=2x^2+x+6
3x-x=6-4
2x=2
x=1


Answered by rockuttam2005
2

Answer:

is x=0,-7

Step-by-step explanation:

What will be the answer of (x+1) /2 + 2/(x+1) = (x+1) /3 + 3/(x+1) - 5/6?

Let us Take is

(x+1)/2+2/(x+1)=(x+1)/3+3/(x+1)-5/6

I hope ur real number are one site and other site is x by numerical

(X+1)/2-(x+1)/3+5/6=3/(x+1)-2/(x+1)

Take both site LCM

[(X+1)*3-(x+1)*2+5)]/6=3-2/(x+1)

(3x+3–2x-2+5)(x+1)=1*6

(X+6)(x+1)=6

X^2+x+6x+6=6

X^2+7x+6–6=0

X^2+7x=0,. x(x+7)=0

Consider that x=0 ,x+7=0

So that answer is x=0,-7

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