Question

(x-1)^2=(2x+3) comparing with ax^2+bx +c=0,b=?? ​

Answer 1

Answer:

(x-1)²=(2x+3).

(x-1)²=x²+1²-2(x)(1). (Because (a-b)²=a²+b²-2ab where a=x & b=1).

=x²+1-2x.

(x-1)²-(2x+3)=0.

x²+1-2x-2x-3=0. (Because -×+=-).

x²+4x-2=0. (Because -×-=+ & +×-=- & largest number is important).

ax²+bx+c=0.

a=1, b=4 & c=-2.

b=4.

I think this is your answer.