Question

( x -1)² - 5(x-1) -6 = 0
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Answer 1

Let, x-1 = t

Then, according to the question :

t² - 5t - 6

=> t²-6t+t-6 = 0

=> t(t-6)+1(t-6) = 0

=> (t-6)(t+1) = 0

t = 6 and -1

When t = 6 then, x = 6+1 = 7

when t = -1 then, x = -1+1 = 0

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Answer 2

Answer: 7

Step-by-step explanation:

x^2 +1 - 2x - 5x +5 -6 = 0

x^2 - 7x = 0

x^2 = 7x

x = 7